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The diagonal of a rectangular field is 60 meters more than the shorter side.If the longer side is 30 meters more than the shorter side,find the side of the field. |
Answer» Given:-To find:-
Solutions:-
Then,Larger side of the rectangle = (x + 30)m Diagonal of the rectangle = √x² + (x + 30)² The diagonal of the rectangle is 60 m more that the shorter side.Therefore,=> √x² + (x + 30)² = x + 60 => x² + (x + 30)² = (x + 60)² => x² + x² + 900 + 60X = x² + 3600 + 120x => x² - 60x - 2700 = 0 => x² - 90x + 30x - 2700 = 0 => x(x - 90) + 30(x + 90) = 0 => (x - 90) (x + 30) = 0 => x - 90 = 0 or x + 30 = 0 => x = 90 or x = - 30
Therefore,The LENGTH of the shorts side be 90m length of the larger side be (90 + 30) = 120m Hence, the side of the field is 120m. |
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