The diagnols of a rhombas are 8cm and 6cm. Find the length of each sid

1.	The diagnols of a rhombas are 8cm and 6cm. Find the length of each side of the rhombas
Answer» Answer: 5 cm Step-by-step explanation: SINCE diagonals of rhombus ABCD divides the rhombus into 4 parts, let's take ∆AOB from rhombus (O is the point of intersection of diagonal AC and BD). Since it is right-angled at angle AOB, using the Pythagoras's theorem, we can say that (AO)^2 + (OB)^2 = (AB)^2 => 4^2 + 3^2 = (AB)^2 {Diagonals of rhombus are perpendicular BISECTOR of each other} =>16 + 9 = (AB)^2 => 25 = (AB)^2 => 5 = AB Therefore SIDE of rhombus is 5cm.

The diagnols of a rhombas are 8cm and 6cm. Find the length of each side of the rhombas

Answer»

Answer:

5 cm

Step-by-step explanation:

SINCE diagonals of rhombus ABCD divides the rhombus into 4 parts, let's take ∆AOB from rhombus (O is the point of intersection of diagonal AC and BD).

Since it is right-angled at angle AOB, using the Pythagoras's theorem, we can say that (AO)^2 + (OB)^2 = (AB)^2

=> 4^2 + 3^2 = (AB)^2 {Diagonals of rhombus are perpendicular BISECTOR of each other}

=>16 + 9 = (AB)^2

=> 25 = (AB)^2

=> 5 = AB

Therefore SIDE of rhombus is 5cm.

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The diagnols of a rhombas are 8cm and 6cm. Find the length of each side of the rhombas

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