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The density of ice is `xgm//c c` and that of water is `y gm//c c`. What is the change in volume in `c c`, when `m gm` of ice metls?A. `m(y-x)`B. `(y-x)//m`C. `mxy(x-y)`D. `m(1//y-1//x)` |
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Answer» `m=` volume `xx` density Mass remain constant. `V_(ice)xxrho_(ice)=V_(water)xxrho_(water)` `V_(water)=(V_(ice)xxrho_(ice))/(rho_(water))=(m)/(y)` `DeltaV=V_(water)-V_(ice)=(m)/(y)-(m)/(x)=m((1)/(y)-(1)/(x))` |
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