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The density of a non-uniform rod of length `1m` is given by `rho (x) = a (1 + bx^(2))` where a and b are constants and `0 le x le 1`. The centre of mass of the rod will be atA. `(3(2+b))/(4(3+b))`B. `(4(2+b))/(3(3+b))`C. `(3(3+b))/(3(2+b))`D. `(4(3+b))/(3(2+b))` |
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Answer» Correct Answer - A When `b rarr 0`. The density becomes uniform and hence the centre of mass is at `x = 0.5`. Only option (A) tends to `0.5` as `b rarr 0` |
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