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The density of 3 molal sodium thiosulphate is 1.25 g/cm³. The mole fraction of sodium thiosulphate is |
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Answer» (i) Mass of 1000 mL of Na2S2O3 solution = 1.25×1000=1250g Mass of Na2S2O3 in 1000 mL of 3 M solution =3×MolmassofNa2S2O3 =3×158=474g Mass percentage of Na2S2O3 in solution =1250474×100=37.92 Alternatively, M=mAx×d×10 3=158x×1.25×10 x=37.92 (II) No. of moles of Na2S2O3=158474=3 Mass of WATER =(1250−474)=776g No. of moles of water =18776=43.1 Mole fraction of Na2 |
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