the denominator of rational no is greater than its numerator by 7. if

1.	the denominator of rational no is greater than its numerator by 7. if the mumerator is increased by 17 and the deniminator decreased by 6 ,the new no becomes 2. find the original number
Answer» LET the numerator be 'X' Thus, denominator = (x + 7) Thus, fraction = x/(x+7) According to the question, NEW Numerator = x + 17 New denominator = x + 7 - 6 = x + 1 New Fraction = 2 => (x+17)/(x+1) = 2 On cross-multiplying we get, x + 17 = 2(x+1) => x + 17 = 2x + 2 => 2x - x = 17 - 2 => x = 15 Thus original numerator = 15 and original denominator = 15 + 7 = 22 Thus, original fraction = 15/22

the denominator of rational no is greater than its numerator by 7. if the mumerator is increased by 17 and the deniminator decreased by 6 ,the new no becomes 2. find the original number

Answer»

LET the numerator be 'X'

Thus, denominator = (x + 7)

Thus, fraction = x/(x+7)

According to the question,

NEW Numerator = x + 17

New denominator = x + 7 - 6 = x + 1

New Fraction = 2

=> (x+17)/(x+1) = 2

On cross-multiplying we get,

x + 17 = 2(x+1)

=> x + 17 = 2x + 2

=> 2x - x = 17 - 2

=> x = 15

Thus original numerator = 15 and

original denominator = 15 + 7 = 22

Thus, original fraction = 15/22

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the denominator of rational no is greater than its numerator by 7. if the mumerator is increased by 17 and the deniminator decreased by 6 ,the new no becomes 2. find the original number​

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the denominator of rational no is greater than its numerator by 7. if the mumerator is increased by 17 and the deniminator decreased by 6 ,the new no becomes 2. find the original number