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The deflection of a beam is given by y = 2x^3-9x^2+12x. Find themaximum deflection. |
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Answer» By comparing d/dx with 0 we will get max value of xso dy/dx=6x^2-18x+12=0so x^2-3x+2=0so x=1 and 2so when x=1 y=2-9+12=5when x=2 y=16-36+24=4so max deflection=5 |
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