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The decay constant of a radioactive substance is 0.173 `("years")^(-1)`. Therefore:A. Nearly 63% of the radioactive substance will decay in (1/0.173) year.B. half life of the radio active substance is (1/0.173) year.C. one-fourth of the radioactive substance will be left after nearly 8 years.D. one-fourth of the radioactive substance will be left after nearly 6 years. |
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Answer» Given `lambda=0.173` `T_(1//2)=(ln2)/(lambda)=0.693/0.173~=4` Also for t 1/0.173 year Remaining nuclei `N=N_(0)e^(-1)=0.37 N_(0)` Decay nuclie=`N_(0)-N=0.63 N_(0)` |
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