1.

The decay constant of 19780Hg (electron capture to 19779Au) is 1.8 ×10−4 S−1. (a) What is the half-life ? (b) What is the average - life ? (c) How much time will it take to convert 25% of this isotope of mercury into gold ?

Answer»

The decay constant of 19780Hg (electron capture to 19779Au) is 1.8 ×104 S1. (a) What is the half-life ? (b) What is the average - life ? (c) How much time will it take to convert 25% of this isotope of mercury into gold ?



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