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the de Broglie wavelength of the electron in the second bohr orbit is given the radius of a first orbit is 0.53 ampheres |
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Answer» The de Broglie's WAVELENGTH of electron present in first Bohr orbit of 'H' ATOM is 2π×0.529 Ao .First Bohr orbit of 'H' atom has radius r=0.529A o ALSO, the angular MOMENTUM is quantised.mvr= 2πh 2πr= mvh =λλ=2π×0.529 Ao EXPLANATION: |
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