1.

The de Broglie wavelength of an electronin an orbit representedby the orbital diagram is(A) 10A​

Answer»

de Broglie WAVELENGTH SAY l

l = h/mv

and mvr=nh/2π

so l = 2πr/n

r value can be FOUND be 0.529×n² A° formula

now you can SUBSTITUTE and find out the answer



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