The de Broglie wavelength of a photon is twice the de Broglie waveleng – InterviewSolution

1.

The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is ve=c/100. Then(a) Ee/Ep=10-4(b) Ee/Ep =10-2(c) Pe/meC=10-2(d) Pe/meC=10-4

Answer»

(b), (c)

(b) E_e/E_p =10^-2

(c) P_e/m_eC=10^-2

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