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The curve c has equation y = (x-2)(x-a)/(x-1)(x-3) where a is a constant not equal to 1,2 or 3(i) write down the equation of the asymptotes of c(ii) show that c meets the asymptote parallel to the x-axis at the point where x = (2a-3)/(a-2)(iii) show that the x-coordinates of any stationary points on C satisfy (a-2)x^2 + (6 - 4a)x + (5a-6) = 0and hence find the set of values of a for which c has stationary points(iv) sketch the graph of c for (a) a > 3(b) 2 < a < 3 |
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Answer» Answer: The graph of y f(X) is transformed into the graph of y f(- x) by a reflection in the y-axis. Hence the new curve has equation y 2 tan (- x). However, since tan(- x) - tan x, the equation of the new curve can be written as y 2 - tan x. (B) Recall that a translation of - transforms the graph of y f(x) into the graph of y f(x - a) b. After translation through the vector - , the curve y 2 tan x has equation y 2 tan x - 3 5 or y 7 tan x - 3 . (C) The graph of y f(x) is transformed into the graph of y f x c by a stretch of scale factor c in the x-direction. Hence y 2 tan x is transformed into y 2 tan 0 x .5 or y 2 tan 2x. |
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