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The current is a solenoid of 240 turns, having a length of 12 cm and a radius of 2 cm, changes at a rate of `0.8 A s^(-)`. Find the emf indcued in it. |
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Answer» Here, `N = 240, l = 12 cm = 12 xx 10^(2) m`, `r = 2 cm = 2 xx 10^(-2) m, A = pi r^(2)` `dI//dt = 0.8 As^(-1), e = ?` `L = (mu_(0) N^(2) A)/(l) = (4 pi xx 10^(-7) (240)^(2) xx pi (0.02)^(2))/(0.12)` `|e| = (L dI)/(dt) = (4 pi xx 10^(-7) (240)^(2) xx 3.14 xx 4 xx 10^(-4) xx 0.8)/(0.12)` `= 6 xx 10^(-4) V` |
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