The current in the given circuit will be :

1.	The current in the given circuit will be :
Answer» Answer: 0.1A Explanation: LET US Assume the Three Resistors as R1, R2 & R3 ∴ R1 & R2 are in Series ∴Rs = R1 + R2 = 30 + 30 = 60 Ohms Rs = 60 Ohms By PUTTING R1 & R2 in Series, They become as a Single Resistor. ∵ R1 & R2 have became as a Single Resistor ∴ Rs & R3 are in PARALLEL Connection ∴ 1/Rp = 1/Rs + 1/R3 = 1/60 + 1/30 = 2 + 1/60 1/Rp = 3/60 Rp = 60/3 = 20 Rp = 20 Ohms W.K.T V = IR I = V/R I = 2/20 I = 1/10 I = 0.1 I= 0.1 A I Hope this Explanation will be helpful to You...

Answer»

Answer:

0.1A

Explanation:

LET US Assume the Three Resistors as R1, R2 & R3

∴ R1 & R2 are in Series

∴Rs = R1 + R2

= 30 + 30

= 60 Ohms

Rs = 60 Ohms

By PUTTING R1 & R2 in Series, They become as a Single Resistor.

∵ R1 & R2 have became as a Single Resistor

∴ Rs & R3 are in PARALLEL Connection

∴ 1/Rp = 1/Rs + 1/R3

= 1/60 + 1/30

= 2 + 1/60

1/Rp = 3/60

Rp = 60/3

= 20

Rp = 20 Ohms

W.K.T

V = IR

I = V/R

I = 2/20

I = 1/10

I = 0.1

I= 0.1 A

I Hope this Explanation will be helpful to You...

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