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The current in an inductive circuit is given by 0.3 sin(200t - 40^(@)) A. Write the equation for the voltage across it if the inductance is 40 mH. |
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Answer» SOLUTION : `L = 40 xx10^(-3H), i = 0.1 sin (200t-40^(@)), X_(L) = omegaL= 200 x× 40 x× 10^(-3) = 8Omega, V_(m)=I_(m)X_(L)= 0.3 xx 8 = 2.4 V` In an INDUCTIVE circuit, the voltage leads the current by `90^(@)` THEREFORE, `upsilon = V_(m) sin (omega +90^(@))` `upsilon = 2.4 sin (200t - 40^(@)+90^(@))` `upsilon = 2.4 sin (200t +50^(@))vol t` |
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