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The current (in Ampere) in an inductor is given by `l=5+16t`, where `t` in seconds. The selft - induced emf in it is `10mV`. Find (a) the self-inductance, and (b) the energy stored in the inductor and the power supplied to it at `t =1s` |
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Answer» a. `dI//dt=16A//s` `:.L=|e/(dI//dt)|=(10xx10^-3)/16` `=0.625xx10^-3H=0.625mH` b. At `t=1s, I=21A` `U=1/2LI^2=1/2xx(0.625xx10^-3)(21)^2` `=0.137J` `P=Ei=(10xx10^-3)(21)` `=0.21J//s` |
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