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The current in a coil of self-inductance `4H` is given by `i=4sint^(2)` . Find the amount of energy spent during the period when the current changes from `0` to `4A` . |
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Answer» When the current in the coil is variable, small work done in time `dt` `dW=Pdt=eidt=(L(di)/(dt))idt=Lidi` `W=Lint_(0)^(4)idi` `=4|(i^(2))/(2)|_(0)^(4)=32J` |
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