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The current (I) and voltage (V) graphs for a given metallic wire at two different temperature `(T_(1))` and `(T_(2))` are shown in fig. It is concluded that A. `T_(1) lt T_(2)`B. `T_(1) gt T_(2)`C. `T_(1) = T_(2)`D. `T_(1) = 2T_(2)` |
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Answer» Correct Answer - B Slope of graph `V-I = (1)/("Resistance")` `R_(2) gt R_(1)` So` T_(2) gt T_(1)` |
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