1.

The current flow in a given circuit will be:(a) 2.5 A(b) 0.75 A(c) 0.5 A(d) 0.25 A

Answer»

(d) 0.25 A
From Kirchhoff’s second law
ΣE = IR
2 – 4 = -2I – 5I – I
-2 = -8I
I = \(\frac{2}{8}\frac{1}{4}=\) 0.25 A


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