1.

The cost of table salt `(NaCl)` and table sugar `(C_(12)H_(22)O_(11))` are Rs 2 per kg and Rs. 6 per kg respectively. Calculate their cost per mole.

Answer» (a) Cost of table salt `(NaCl)` per mole
Gram molecular mass of `NaCl=23+35.5 = 58.5 g`
Now, 1000 g of NaCl cost = Rs. 2
`:. 58.5 g` of NaCl will cost `= (2)/((1000 g))xx(58.5 g)=0.117` Rupee `=0.117 xx 100 = 12` paise (approx)
(b) Cost of table sugar `(C_(12)H_(22)O_(11))` per mole
Gram molecular mass of `C_(12)H_(22)O_(11)=12xx12+22xx1+16xx11=144+22+176=342`g
Now, 1000g of sugar cost = Rs. 6
`:. 342g` of sugar will cost `= (6)/((1000 g))xx(342 g)=2.052 = 2.0` Rupees (approx)


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