The cost of diamond varies with square of its weight. The diamond of w

1.	The cost of diamond varies with square of its weight. The diamond of worth Rs. 9000 is accidently dropped and broke into 3 pieces. The ratio of weight of pieces is 3 : 2 : 1. Find the loss occurred.1. Rs. 55002. Rs. 60003. Rs. 45004. Rs. 65005. RS. 5000
Answer» Correct Answer - Option 1 : Rs. 5500 GIVEN : The ratio of weight of pieces is 3 : 2 : 1 The diamond of worth Rs. 9000 is accidently dropped and broke into 3 pieces. CONCEPT : The cost of a piece of diamond varies with the square of its weight. ⇒ Price = k × weight²......(k is any constant) ASSUMPTION : Let the weight of a piece of diamond be (3a + 2a + a = 6a) CALCULATION : The initial value of diamond = 36ka² ⇒ 36ka² = 9000 Then, The new value of diamond becomes = k (9a² + 4a²+ a²) = 14ka² New value of diamond = (14 × 9000)/36 = Rs. 3500 ∴ Loss occurred = 9000 - 3500 = Rs. 5500

The cost of diamond varies with square of its weight. The diamond of worth Rs. 9000 is accidently dropped and broke into 3 pieces. The ratio of weight of pieces is 3 : 2 : 1. Find the loss occurred.1. Rs. 55002. Rs. 60003. Rs. 45004. Rs. 65005. RS. 5000

Answer» Correct Answer - Option 1 : Rs. 5500

GIVEN :

The ratio of weight of pieces is 3 : 2 : 1

The diamond of worth Rs. 9000 is accidently dropped and broke into 3 pieces.

CONCEPT :

The cost of a piece of diamond varies with the square of its weight.

⇒ Price = k × weight²......(k is any constant)

ASSUMPTION :

Let the weight of a piece of diamond be (3a + 2a + a = 6a)

CALCULATION :

The initial value of diamond = 36ka²

⇒ 36ka² = 9000

Then,

The new value of diamond becomes = k (9a² + 4a²+ a²) = 14ka²

New value of diamond = (14 × 9000)/36 = Rs. 3500

∴ Loss occurred = 9000 - 3500 = Rs. 5500

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