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THE COST OF AN ELECTRICAL GADGET AND THE COST OF PLUMBING MATERIAL WERE IN THE RATIO 8:6 LAST YEAR, THIS YEAR EACH COST HAS REDUCED BY Ghc 4.00 and their ratio changed to 7:5, respectively taking the initial cost of the electrical gadget to be Ghep and that of the plumbing material to be Ghe q, calculate the value of p and q |
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Answer» Given : cost of an ELECTRICAL gadget and the cost of a plumbing material were in the ratio 8:6 last year. This year, each cost was reduced by 4.00 and has changed to 7:5 respectively To find : initial cost of the electrical gadget & plumbing material Solution: cost of an electrical gadget = 8x = p cost of a plumbing material = 6x = q each cost was reduced by 4.00 cost of an electrical gadget = 8x - 4 cost of a plumbing material = 6x - 4 New ratio 7 : 5 => (8x - 4)/ (6x - 4) = 7/5 => 5(8x - 4) = 7(6x - 4) => 40x - 20 = 42x - 28 => 2x = 8 => x = 4 p = 8x = 8 * 4 = 32 q = 6x = 6 * 4 = 28 initial cost of the electrical gadget p = 32 initial cost of the plumbing material q = 28 Learn More: The ratio of the number of students in THREE classes A,B and C is 3:7 ... The ratio of linear to volume expansion of a cube is 1:12. Find side ... |
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