1.

The correct order of dipole moments of HF, H_(2)S and H_(2)O is :

Answer»

`HF LT H_(2)S lt H_(2)O`
`HF lt H_(2)S gt H_(2)O`
`HF gt H_(2)S gt H_(2)O`
`HF gt H_(2)O gt H_(2)S`

Solution :Higher the ELECTRONEGATIVITY DIFFERENCE, higher will be the polarity F is most electronegative followed by Oand then S.


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