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The correct order of decreasing H-C-H angle in the following molecule is |
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Answer» `I gt II gt III`  Look at the structure carefully. In cyclopropane, C-C bonds are bent and not pure `sigma`-bonds. Overlapping is greatest when orbitals overlap "end-on." i.e. VIA `sigma`-bonding. `PI`-bonds overlap laterally. The overlap in cyclopropane is NEITHER end-on nor lateral but in between. So, it is intermediate between `sigma`- and `pi`-bonding.   THUS, the corect order of decreasing H-C-H angle is,II `gt I gt III` |
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