1.

The correct order of decreasing acidic nature of H_(2)O, ROH, CH -= CH and NH_(3) is

Answer»

`CH -= CH gt H_(2)O ROH gt NH_(3)`
`H_(2)O gt ROH gt CH -= CH gt NH_(3)`
`ROH gt NH_(3) gt CH -= CH gt H_(2)O`
`H_(2)O gt ROH gt NH_(3) gt CH -= CH`

Solution :`{:("COMPOUND",,pK_(a)),(ROH,,(16-18)),(H_(2)O,,14),(NH_(3),,4.75 (pK_(b))),(HC -= CH,,26):}`
SMALLER the `pK_(a)` stronger the acid.
`:.` The order of decreasing ACIDIC nature is
`H_(2)O gt ROH gt HC -= CH gt NH_(3)`.


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