1.

The correct order of 2^(nd) ionization potential of carbon, nitrogen , oxygen and fluorine is

Answer»

CgtNgtOgtF
OgtNgtFgtC
OgtFgtNgtC
FgtOgtNgtC

Solution :`C(6) 1s^(2)2s^(2) 2p_(x)^(1) 2p_(y)^(1)"" N(7) 1s^(2)2s^(2)2p_(x)^(1) 2p_(y)^(1) 2p_(z)^(1)`
`O(8) 1s^(2)2s^(2)2p_(x)^(2) 2p_(y)^(1)2p_(z)^(1) "" F(9)1s^(2)2s^(2)2p_(x)^(2)2p_(y)^(2)2p_(z)^(1)`
O has highest `2^(nd)` ionization potential i.e., ionization ENERGY because after LOSING one electron, it acquires stable half filled p-electronic configuration.
F is smaller than N, therefore, it has higher second ionization potential. C has least due to BIGGER size.


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