1.

The correct order for the wavelength of absorption in the 27. visible region is :

Answer»

`[Ni(NO_(2))_(6)]^(4-) lt [Ni(NH_(3))_(6)]^(2+) lt [Ni(H_(2)O)_(6)]^(2+)`
`[Ni(NO_(2))_(6)]^(4-) lt [Ni(H_(2)O)_(6)]^(2+) lt [Ni(NH_(3))_(6)]^(3+)`
`[Ni(H_(2)O)_(6)]^(2+) lt [Ni(NH_(3))_(6)]^(2+) lt [Ni(NO_(2))_(6)]^(4-)`
`[Ni(NH_(3))_(6)]^(2+) lt [Ni(H_(2)O)_(6)]^(2+) lt [Ni(NO_(2))_(6)]^(4-)`

Solution :For any metal cation,, the magnitude of `Delta_(0)` depends upon the nature of ligand. Higher the value of `Delta_(0)`, LOWER will be the WAVE length absorbed. `Delta_(0)` is crystal field stabilisation energy.
The value of `Delta_(0)` for ligands varies as follows
`H_(2)O lt NH_(3) lt NO_(2)^(-)`
so, the wavelength absorbed will vary in REVERSE order
`NO_(2)^(-) lt NH_(3) lt H_(2)O`.


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