1.

The correct option(s) to distinguish nitrate salts of Mn^(2+)" and Cu^(2+) taken separately is (are)

Answer»

`MN^(2+)` show the characteristic green colour in the flame test
Only `Cu^(2+)` show the formation of precipitate by passing `H_(2)S` in acidic MEDIUM
Only `Mn^(2+)` show the formation of precipitate by passing `H_(2)S` in faintly basic medium
`Cu^(2+)//Cu` has higher reduction potential than `Mn^(2+)//Mn` (measured under similar conditions).

Solution :(b,d) Both these are correct.
(b) In weakly acidic medium, only `Cu^(2+)` ions form black precipitate of CuS.
(d) `E_(Cu^(2+)//Cu)^(@)(+0.34V)` is higher than that of `E_(Mn^(2+)//Mn)^(@)(-1.18V)`
The other two options are not correct.
(a) `Cu^(2+)" and not "Mn^(2+)` shows characteristic green colour in the flame test.
(c) Both `Cu^(2+)" and "Mn^(2+)` show the formation of precipitate (CuS-Black) & MnS-Brown) by passing `H_(2)S` in faintly basic medium.


Discussion

No Comment Found