1.

The correct IUPAC name of the compound is

Answer»

4 - ethyl -3- PROPYL HEX -1 - ENE
3 - ethyl -4- ethenyl heptane
3 - ethyl -4- propyl hex -1- ene
3 (1- ethylpropyl hex -1- ene

Solution :The given compound is

4 - Ethyl - 3 - propylhex - 1 - ene


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