1.

The copounds which is not coloured is

Answer»

`K_(4)Fe(CN)_(6)`
`K_(3)Fe(CN)_(6)`
`Na_(2)CdCl_(4)`
`Na_(2)CuCl_(4)`

Solution :In `Na_(2)CD Cl_(4)`, Cd has oxidatin state +2.
So, its ELECTRONIC configuration is `4d^(10)4s^(0)`
All the 4d orbitals are fully filled.
hence, there will not be d-d transition resulting in colour. So, it is colourless.


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