The coordinates of the vertices of a triangle ABC are A(2, 4), B(5, 1)

1.	The coordinates of the vertices of a triangle ABC are A(2, 4), B(5, 1), C(-1, -1). find the equation of the median drawn from vertex A
Answer» $\underline{\textsf{Given:}}$ $\textsf{Vertices of triangle ABC are}$ $\textsf{A(2, 4), B(5, 1), C(-1, -1)}$ $\underline{\textsf{To find:}}$ $\textsf{The equation of median drawn from vertex A}$ $\underline{\textsf{Solution:}}$ $\textsf{Median from A is a line segment joining A and the midpoint}$ $\textsf{of the side BC}$ $\textsf{Midpoint of side BC}$ $\mathsf{(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})}$ $\mathsf{(\dfrac{5+(-1)}{2},\dfrac{1+(-1)}{2})}$ $\mathsf{(\dfrac{4}{2},\dfrac{0}{2})}$ $\mathsf{(2,0)}$ $\textsf{Now}$ $\textsf{The equation of median drawn from A}$ $\textsf{is the equation of the line joining (2,4) and (2,0)}$ $\mathsf{\dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}}$ $\mathsf{\dfrac{y-4}{0-4}=\dfrac{x-2}{2-2}}$ $\mathsf{\dfrac{y-4}{-4}=\dfrac{x-2}{0}}$ $\implies\boxed{\mathsf{x-2=0}}$ $\underline{\textsf{Answer:}}$ $\textsf{The equation of the median drawn from A is x-2=0}$