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The conversion of the molecules X to Y follows second order kinetics. If the concentration X is increased to three times, how will it affect the rate of formation of Y? |
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Answer» Solution :For the reaction, `X to Y`, as it follows second order kinetics, the rate law equation will be Rate `=K[X]^(2)` If concentration of X is increased to three times, then Rate `=k[3X]^(2) "orRate"=9K[X]^(2)` Thus, the RTE of reaction will become 9 times. Hence, the rateof formation of Y will INCREASE 9 times. |
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