Saved Bookmarks
| 1. |
The conversion of the molecules X to Y follows second order kinetics. If the concentration X is increased to three times, how will it affect the rate of formation of Y ? |
|
Answer» Solution :For the reaction, `XtoY`, as it follows SECOND order KINETICS, the rate LAW equation will be Rate `=k[X]^(2)=ka^(2)""("if "[X]=a" mol L"^(-1))` If concentration of X is increased three times, now, `[X]=3"a mol L"^(-1)` `:."""Rate"=k(3" a")^(2)=9" ka"^(2)` Thus, the rate of reaction will become 9 times. Hence, the rate of FORMATION of Y will increase 9 times. |
|