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The conversion of molecules X to Y follows second order kinetics.If concentration of X is increased to three times how will it affect the rate of formation of Y? |
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Answer» Solution :Given reaction X `to` Y Order of reaction =2 `therefore Rate r_(1)=-K[x]^(2)` Now,the CONCENTRATION of X increase to THREE time then new concentration is =3X mol `L^(-1)` `therefore New rate r_(2)=k[3X]^(2)=9K [x]^(2)` `therefore (r_(2))/(r_(1))=(9k[X]^(2))/(k[X]^(2))=9` So ,new rate is nine times. `therefore` so,it will effect nine times in the rate of formation of Y. |
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