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The conversion of molecules x to y follows second order kinetics. It concentration of x is increased to three times how will it affect the rate of formation of y ? For the reaction x rarr y as it follows second order kinetics wherefore the rate of formation of y ? |
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Answer» SOLUTION :Rate `=k[x]^(2)=KA^(2)` `[x]="a mol"^(-1)` If the concentration of x is incross three time, then `(x)=3"a mol L"^(-1)` Rate `= R(3A)^(2)=9 ka^(2)` Hence, the rate of formation will increase by 9 times. |
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