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The conversion of molecules X to Y follows second order kinetics . If concentration of X is increased to three times how will it affect the rate of formation of Y ? |
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Answer» Solution :For the REACTION , `X rarrY` as it follows second order kinetics , therefore the rate law EQUATION will be Rate `=k[X]^2=ka^2` if`[X]= "a mol"^(-1)` If the CONCENTRATION of X is increased three times , then `[X] = 3 " a mol L"^(-1)` `:.` Rate `=k(3A)^2=9ka^2` Thus, the rate of the reaction will become 9 times. Hence the rate of FORMATION of Y will increase by 9 times. |
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