1.

The conversion of A to B follows second order kinetics. Doubling the concentration of A will increases the rate of formation of B by a factor of

Answer»

`1//4`
`1//2`
4
2

Solution :`"Rate"_(1) = K[A]^(2)`
`"Rate"_(2) = K[2A]^(2) = 4K[A]^(2)`
`RARR ("Rate"_(2))/("Rate"_(1)) = 4 rArr "Rate"_(2) = 4 XX "Rate"_(1)`


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