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The conductivity of solution prepared by dissolving 10−7 mole of AgNO3 in 1 litre of saturated aqueous solution of AgBr having Ksp of AgBr = 12×10−14 and λ0Ag+, λ0Br−, λ0NO−3 as 6×10−3, 8×10−3 and 7×10−3Sm2mol−1 respectively and neglecting contribution of solvent is found to be equal to p×10–6Sm–1 then, the value of p is

Answer» The conductivity of solution prepared by dissolving
107 mole of AgNO3 in 1 litre of saturated aqueous solution of AgBr having
Ksp of AgBr = 12×1014 and λ0Ag+, λ0Br, λ0NO3 as 6×103, 8×103 and 7×103Sm2mol1 respectively and neglecting contribution of solvent is found to be equal to p×106Sm1
then, the value of p is


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