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The conductivity of NaCl at 298K has been determined at different concentrations and the results are given below: {:("Concentration/M",0.001,0.010,0.020,0.050,0.100),(10^(2)xxkappa//S" "m^(-1),1.237,11.85,23.15,55.53,106.74):} Calculate wedge for all concentrations and draw a plot between wedge and c^(1//2). find the value of wedge^(8). |
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Answer» Solution :1 S `cm^(-1)=100" S "m^(-1)` `(1" S "cm^(-1))/(100" S "cm^(-1))=1` (UNIT conversion FACTOR) `(AA)^(@)=`intercept on the `(AA)_(m)` axis=124.0 S `cm^(2)mol^(-1)` (on extrapotation to zero CONCENTRATION). |
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