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The conductivity of a saturated solutior of a sparingly soluble salt MX_2 is found to be 4 xx 10^(-5) Omega^(-1) cm^(-1)." If "lambda_(m)^(oo) (1/2 M^(2+))=50 Omega^(-1) cm^(2) mol^(-1) and lambda^(oo) (X^(-))=50 Omega^(-1) cm^(2) mole^(-1), the solubility product of the salt is about |
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Answer» `2 xx 10^(-10)M^(3)` |
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