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The conductivity of a 0.01 M solution of acetic acid at 298 K is 1.65 xx 10^(-4 )S cm^(-1).Calculate molar conductivity (Lambda_(m))of the solution. |
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Answer» SOLUTION :Use the relation, `Lambda_(m) = (1000 k)/C`, where C stands for CONCENTRATION SUBSTITUTING the values, we get `Lambda_(m) = (1000 xx 1.65 xx 10^(-4))/0.01 = 16.5 S cm^(2) MOL^(-1)` |
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