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The conductivity of 0.20M solution of KCl of 298K is 0.0248 S cm^-1. Calculate its molar conductivity. |
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Answer» SOLUTION :`A_m=(K times 1000)/(MOLARITY)` `=(0.0248 S cm^-1 times1000cm^3 L^-1)/(0.20 mol L^-1)` `=124 S cm^2 mol^-1` |
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