The conductivity of 0.20M solution of KCl at 298K is 0.0248 S cm^(-1) – InterviewSolution

1.	The conductivity of 0.20M solution of KCl at 298K is 0.0248 S cm^(-1) . Calculate its molar conductivity.
Answer» SOLUTION :`"MOLAR conductivity"=(kxx1000)/(M)=("0.0248 S cm"^(-1)XX"1000 cm"^(3)L^(-1))/("0.2 mol L"^(-1))` `="124.0 S cm"^(2)"mol"^(-1)`

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