1.

The conductivity of 0.20M solution of KCL at 298K is 0.025 S cm^-1. Calculate its molar conductivity.

Answer»

SOLUTION :CONCENTRATION of solution =0.20 M
Conductivity =`0.025 S cm^-1`
Molar conductivity `A_m`
`=("Conductivity (K) TIMES 1000")/("Concentration of solution ")`
`=(0.025 times 1000)/0.20`
`=125 S cm^2 mol^-1`


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