Saved Bookmarks
| 1. |
The conductivity of 0.20 M solution of KCl at 298K is 0.0248 S cm^(-1). Calculate its molar conductivity. |
| Answer» SOLUTION :`wedge_(m)=(kappaxx1000)/("MOLARITY")=(0.0248" S "cm^(-1)xx1000cm^(3)L^(-1))/(0.20" mol "L^(-1))=124" S "cm^(2)mol^(-1)` | |