Saved Bookmarks
| 1. |
The conductivity of 0.20 M solution of KCI at 298 K is 0.0248 S cm^(-1).Calculate its molar conductivity. |
|
Answer» Solution :Applying the FOLLOWING relation and substituting the values, we get: `Lambda_(m) = (k xx 1000)/("MOLARITY") = (0.0248 S CM^(-1) xx 1000 cm^(3) L^(-1))/(0.20 mol L^(-1)) = 124 S cm^(2) mol^(-1)`. |
|