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The conductivity of 0.1 M KCl solution is 1.29 S m^(-1). If the resistance of the cell filled with 0.1 M KCl is 100 Omega, Calculate the cell constant. |
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Answer» Solution :The cell constant filled with electrolytic solution is GIVEN as , Cell constant = conductivity `xx` RESISTANCE. Cell constant `=1.29m^(-1)XX100 Omega` `=129m^(-1)=1.29cm^(-1)`. |
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