1.

The conductivity of 0.01 mol L^(-1)KCl solution is 1.41xx10^(-3)" S "cm^(-1). What is the molar conductivity (S cm^(2) mol^(-1)) ?

Answer»

14.1
1.41
1410
141

Solution :(d) MOLAR conductivity`(Lambda_(m))=(1000xxk)/(M)`
`=(1000xx(1.41xx10^(-3)" S " cm^(-1)))/((0.01" MOL "cm^(-3)))=141" S "cm^(-2)mol^(-1)`


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