1.

The conductivity of 0.001 M acetic acid is 5 xx 10^(-5) S cm^(-1) and ^^""^(0) is 390.5 S cm^(2) "mol" ^(-1) then the calculated value of dissociation constant of acetic acid would be

Answer»

`81.78 XX 10^(-4)`
`81.78 xx 10^(-5)`
`18.78 xx 10^(-6)`
`18.78 xx 10^(-5)`

ANSWER :C


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